AE 03: NYC flights + data wrangling
Suggested answers
Important
These are suggested answers. This document should be used as reference only, it’s not designed to be an exhaustive key.
Exercise 1
Your turn: Fill in the blanks:
The flights data frame has 336776 rows. Each row represents a flight.
Exercise 2
Your turn: What are the names of the variables in flights.
colnames(flights) [1] "year" "month" "day" "dep_time"
[5] "sched_dep_time" "dep_delay" "arr_time" "sched_arr_time"
[9] "arr_delay" "carrier" "flight" "tailnum"
[13] "origin" "dest" "air_time" "distance"
[17] "hour" "minute" "time_hour"
Exercise 3 - select()
- Demo: Make a data frame that only contains the variables
dep_delayandarr_delay.
flights |>
select(dep_delay, arr_delay)# A tibble: 336,776 × 2
dep_delay arr_delay
<dbl> <dbl>
1 2 11
2 4 20
3 2 33
4 -1 -18
5 -6 -25
6 -4 12
7 -5 19
8 -3 -14
9 -3 -8
10 -2 8
# ℹ 336,766 more rows
- Demo: Make a data frame that keeps every variable except
dep_delay.
flights |>
select(-dep_delay)# A tibble: 336,776 × 18
year month day dep_time sched_dep_time arr_time sched_arr_time arr_delay
<int> <int> <int> <int> <int> <int> <int> <dbl>
1 2013 1 1 517 515 830 819 11
2 2013 1 1 533 529 850 830 20
3 2013 1 1 542 540 923 850 33
4 2013 1 1 544 545 1004 1022 -18
5 2013 1 1 554 600 812 837 -25
6 2013 1 1 554 558 740 728 12
7 2013 1 1 555 600 913 854 19
8 2013 1 1 557 600 709 723 -14
9 2013 1 1 557 600 838 846 -8
10 2013 1 1 558 600 753 745 8
# ℹ 336,766 more rows
# ℹ 10 more variables: carrier <chr>, flight <int>, tailnum <chr>,
# origin <chr>, dest <chr>, air_time <dbl>, distance <dbl>, hour <dbl>,
# minute <dbl>, time_hour <dttm>
- Demo: Make a data frame that includes all variables between
yearthroughdep_delay(inclusive). These are all variables that provide information about the departure of each flight.
flights |>
select(year:dep_delay)# A tibble: 336,776 × 6
year month day dep_time sched_dep_time dep_delay
<int> <int> <int> <int> <int> <dbl>
1 2013 1 1 517 515 2
2 2013 1 1 533 529 4
3 2013 1 1 542 540 2
4 2013 1 1 544 545 -1
5 2013 1 1 554 600 -6
6 2013 1 1 554 558 -4
7 2013 1 1 555 600 -5
8 2013 1 1 557 600 -3
9 2013 1 1 557 600 -3
10 2013 1 1 558 600 -2
# ℹ 336,766 more rows
- Demo: Use the
selecthelpercontains()to make a data frame that includes the variables associated with the arrival, i.e., contains the string"arr\_"in the name.
Exercise 4 - slice()
- Demo: Display the first five rows of the
flightsdata frame.
flights |>
slice(1:5)# A tibble: 5 × 19
year month day dep_time sched_dep_time dep_delay arr_time sched_arr_time
<int> <int> <int> <int> <int> <dbl> <int> <int>
1 2013 1 1 517 515 2 830 819
2 2013 1 1 533 529 4 850 830
3 2013 1 1 542 540 2 923 850
4 2013 1 1 544 545 -1 1004 1022
5 2013 1 1 554 600 -6 812 837
# ℹ 11 more variables: arr_delay <dbl>, carrier <chr>, flight <int>,
# tailnum <chr>, origin <chr>, dest <chr>, air_time <dbl>, distance <dbl>,
# hour <dbl>, minute <dbl>, time_hour <dttm>
- Demo: Display the last two rows of the
flightsdata frame.
flights |>
slice_tail(n = 2)# A tibble: 2 × 19
year month day dep_time sched_dep_time dep_delay arr_time sched_arr_time
<int> <int> <int> <int> <int> <dbl> <int> <int>
1 2013 9 30 NA 1159 NA NA 1344
2 2013 9 30 NA 840 NA NA 1020
# ℹ 11 more variables: arr_delay <dbl>, carrier <chr>, flight <int>,
# tailnum <chr>, origin <chr>, dest <chr>, air_time <dbl>, distance <dbl>,
# hour <dbl>, minute <dbl>, time_hour <dttm>
Exercise 5 - arrange()
- Demo: Let’s arrange the data by departure delay, so the flights with the shortest departure delays will be at the top of the data frame.
flights |>
arrange(dep_delay)# A tibble: 336,776 × 19
year month day dep_time sched_dep_time dep_delay arr_time sched_arr_time
<int> <int> <int> <int> <int> <dbl> <int> <int>
1 2013 12 7 2040 2123 -43 40 2352
2 2013 2 3 2022 2055 -33 2240 2338
3 2013 11 10 1408 1440 -32 1549 1559
4 2013 1 11 1900 1930 -30 2233 2243
5 2013 1 29 1703 1730 -27 1947 1957
6 2013 8 9 729 755 -26 1002 955
7 2013 10 23 1907 1932 -25 2143 2143
8 2013 3 30 2030 2055 -25 2213 2250
9 2013 3 2 1431 1455 -24 1601 1631
10 2013 5 5 934 958 -24 1225 1309
# ℹ 336,766 more rows
# ℹ 11 more variables: arr_delay <dbl>, carrier <chr>, flight <int>,
# tailnum <chr>, origin <chr>, dest <chr>, air_time <dbl>, distance <dbl>,
# hour <dbl>, minute <dbl>, time_hour <dttm>
- Question: What does it mean for the
dep_delayto have a negative value?
Arrived early.
- Demo: Arrange the data by descending departure delay, so the flights with the longest departure delays will be at the top.
# A tibble: 336,776 × 19
year month day dep_time sched_dep_time dep_delay arr_time sched_arr_time
<int> <int> <int> <int> <int> <dbl> <int> <int>
1 2013 1 9 641 900 1301 1242 1530
2 2013 6 15 1432 1935 1137 1607 2120
3 2013 1 10 1121 1635 1126 1239 1810
4 2013 9 20 1139 1845 1014 1457 2210
5 2013 7 22 845 1600 1005 1044 1815
6 2013 4 10 1100 1900 960 1342 2211
7 2013 3 17 2321 810 911 135 1020
8 2013 6 27 959 1900 899 1236 2226
9 2013 7 22 2257 759 898 121 1026
10 2013 12 5 756 1700 896 1058 2020
# ℹ 336,766 more rows
# ℹ 11 more variables: arr_delay <dbl>, carrier <chr>, flight <int>,
# tailnum <chr>, origin <chr>, dest <chr>, air_time <dbl>, distance <dbl>,
# hour <dbl>, minute <dbl>, time_hour <dttm>
-
Your turn: Create a data frame that only includes the plane tail number (
tailnum), carrier (carrier), and departure delay for the flight with the longest departure delay. What is the plane tail number (tailnum) for this flight?
Exercise 6 - filter()
- Demo: Filter the data frame by selecting the rows where the destination airport is RDU.
flights |>
filter(dest == "RDU")# A tibble: 8,163 × 19
year month day dep_time sched_dep_time dep_delay arr_time sched_arr_time
<int> <int> <int> <int> <int> <dbl> <int> <int>
1 2013 1 1 800 810 -10 949 955
2 2013 1 1 832 840 -8 1006 1030
3 2013 1 1 851 851 0 1032 1036
4 2013 1 1 917 920 -3 1052 1108
5 2013 1 1 1024 1030 -6 1204 1215
6 2013 1 1 1127 1129 -2 1303 1309
7 2013 1 1 1157 1205 -8 1342 1345
8 2013 1 1 1240 1235 5 1415 1415
9 2013 1 1 1317 1325 -8 1454 1505
10 2013 1 1 1449 1450 -1 1651 1640
# ℹ 8,153 more rows
# ℹ 11 more variables: arr_delay <dbl>, carrier <chr>, flight <int>,
# tailnum <chr>, origin <chr>, dest <chr>, air_time <dbl>, distance <dbl>,
# hour <dbl>, minute <dbl>, time_hour <dttm>
- Demo: We can also filter using more than one condition. Here we select all rows where the destination airport is RDU and the arrival delay is less than 0.
flights |>
filter(dest == "RDU" & arr_delay < 0)# A tibble: 4,232 × 19
year month day dep_time sched_dep_time dep_delay arr_time sched_arr_time
<int> <int> <int> <int> <int> <dbl> <int> <int>
1 2013 1 1 800 810 -10 949 955
2 2013 1 1 832 840 -8 1006 1030
3 2013 1 1 851 851 0 1032 1036
4 2013 1 1 917 920 -3 1052 1108
5 2013 1 1 1024 1030 -6 1204 1215
6 2013 1 1 1127 1129 -2 1303 1309
7 2013 1 1 1157 1205 -8 1342 1345
8 2013 1 1 1317 1325 -8 1454 1505
9 2013 1 1 1505 1510 -5 1654 1655
10 2013 1 1 1800 1800 0 1945 1951
# ℹ 4,222 more rows
# ℹ 11 more variables: arr_delay <dbl>, carrier <chr>, flight <int>,
# tailnum <chr>, origin <chr>, dest <chr>, air_time <dbl>, distance <dbl>,
# hour <dbl>, minute <dbl>, time_hour <dttm>
-
Your turn: Describe what the code is doing in words.
This code is filtering for flights that landed at either RDU (Raleigh) or GSO (Greensboro) AND either took off early OR landed early.
# A tibble: 6,203 × 19
year month day dep_time sched_dep_time dep_delay arr_time sched_arr_time
<int> <int> <int> <int> <int> <dbl> <int> <int>
1 2013 1 1 800 810 -10 949 955
2 2013 1 1 832 840 -8 1006 1030
3 2013 1 1 851 851 0 1032 1036
4 2013 1 1 917 920 -3 1052 1108
5 2013 1 1 1024 1030 -6 1204 1215
6 2013 1 1 1127 1129 -2 1303 1309
7 2013 1 1 1157 1205 -8 1342 1345
8 2013 1 1 1317 1325 -8 1454 1505
9 2013 1 1 1449 1450 -1 1651 1640
10 2013 1 1 1505 1510 -5 1654 1655
# ℹ 6,193 more rows
# ℹ 11 more variables: arr_delay <dbl>, carrier <chr>, flight <int>,
# tailnum <chr>, origin <chr>, dest <chr>, air_time <dbl>, distance <dbl>,
# hour <dbl>, minute <dbl>, time_hour <dttm>
Hint: Logical operators in R:
| operator | definition |
|---|---|
< |
is less than? |
<= |
is less than or equal to? |
> |
is greater than? |
>= |
is greater than or equal to? |
== |
is exactly equal to? |
!= |
is not equal to? |
x & y |
is x AND y? |
x | y |
is x OR y? |
is.na(x) |
is x NA? |
!is.na(x) |
is x not NA? |
x %in% y |
is x in y? |
!(x %in% y) |
is x not in y? |
!x |
is not x? (only makes sense if x is TRUE or FALSE) |
Exercise 7 - count()
- Demo: Create a frequency table of the destination locations for flights from New York.
flights |>
count(dest)# A tibble: 105 × 2
dest n
<chr> <int>
1 ABQ 254
2 ACK 265
3 ALB 439
4 ANC 8
5 ATL 17215
6 AUS 2439
7 AVL 275
8 BDL 443
9 BGR 375
10 BHM 297
# ℹ 95 more rows
- Demo: In which month was there the fewest number of flights? How many flights were there in that month?
- Your turn: On which date (month + day) was there the largest number of flights? How many flights were there on that day?
Exercise 8 - mutate()
- Demo: Convert
air_time(minutes in the air) to hours and then create a new variable,mph, the miles per hour of the flight.
flights |>
mutate(
hours = air_time / 60,
mph = distance / hours
) |>
select(air_time, distance, hours, mph)# A tibble: 336,776 × 4
air_time distance hours mph
<dbl> <dbl> <dbl> <dbl>
1 227 1400 3.78 370.
2 227 1416 3.78 374.
3 160 1089 2.67 408.
4 183 1576 3.05 517.
5 116 762 1.93 394.
6 150 719 2.5 288.
7 158 1065 2.63 404.
8 53 229 0.883 259.
9 140 944 2.33 405.
10 138 733 2.3 319.
# ℹ 336,766 more rows
- Your turn: Create a new variable to calculate the percentage of flights in each month. What percentage of flights take place in July?
# A tibble: 12 × 3
month n perc
<int> <int> <dbl>
1 1 27004 8.02
2 2 24951 7.41
3 3 28834 8.56
4 4 28330 8.41
5 5 28796 8.55
6 6 28243 8.39
7 7 29425 8.74
8 8 29327 8.71
9 9 27574 8.19
10 10 28889 8.58
11 11 27268 8.10
12 12 28135 8.35
- Demo: Create a new variable,
rdu_bound, which indicates whether the flight is to RDU or not. Then, for each departure airport (origin), calculate what proportion of flights originating from that airport are to RDU.
flights |>
mutate(rdu_bound = if_else(dest == "RDU", "Yes", "No")) |>
count(origin, rdu_bound) |>
group_by(origin) |>
mutate(prop = n / sum(n)) |>
filter(rdu_bound == "Yes")# A tibble: 3 × 4
# Groups: origin [3]
origin rdu_bound n prop
<chr> <chr> <int> <dbl>
1 EWR Yes 1482 0.0123
2 JFK Yes 3100 0.0279
3 LGA Yes 3581 0.0342
Exercise 9 - summarize()
- Demo: Find mean arrival delay for all flights.
Exercise 10 - group_by()
- Demo: Find mean arrival delay for for each month.
# A tibble: 12 × 2
month mean_arr_delay
<int> <dbl>
1 1 6.13
2 2 5.61
3 3 5.81
4 4 11.2
5 5 3.52
6 6 16.5
7 7 16.7
8 8 6.04
9 9 -4.02
10 10 -0.167
11 11 0.461
12 12 14.9
-
Your turn: What is the median departure delay for each airports around NYC (
origin)?